(x^2-2)(x^2-3x+2)=0

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Solution for (x^2-2)(x^2-3x+2)=0 equation: 


Simplifying
(x2 + -2)(x2 + -3x + 2) = 0

Reorder the terms:
(-2 + x2)(x2 + -3x + 2) = 0

Reorder the terms:
(-2 + x2)(2 + -3x + x2) = 0

Multiply (-2 + x2) * (2 + -3x + x2)
(-2(2 + -3x + x2) + x2(2 + -3x + x2)) = 0
((2 * -2 + -3x * -2 + x2 * -2) + x2(2 + -3x + x2)) = 0
((-4 + 6x + -2x2) + x2(2 + -3x + x2)) = 0
(-4 + 6x + -2x2 + (2 * x2 + -3x * x2 + x2 * x2)) = 0
(-4 + 6x + -2x2 + (2x2 + -3x3 + x4)) = 0

Combine like terms: -2x2 + 2x2 = 0
(-4 + 6x + 0 + -3x3 + x4) = 0
(-4 + 6x + -3x3 + x4) = 0

Solving
-4 + 6x + -3x3 + x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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